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Prove thatsen 180C0572 |
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Answer» sin18/ cos72= sin(90-18)/ cos72= cos72/ cos72=1 sin18=sin(90-78) sin(90-♡)=cos(♡) so sin18=cos72 cos72/cos72=1 [tex]nice question [/tex] sin(18)/cos72= sin(90-18)/ cos72= cos72/ cos72=1 sin18/cos72sin(90-72)/cos72cos72/cos721 sin18°/cos72°= sin(90°-72°)/cos72°= cos72°/cos/72°= 1 sin72/cos72=1 is correct answer |
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