1.

Prove thatsen 180C0572

Answer»

sin18/ cos72= sin(90-18)/ cos72= cos72/ cos72=1

sin18=sin(90-78)

sin(90-♡)=cos(♡)

so sin18=cos72

cos72/cos72=1

[tex]nice question [/tex]

sin(18)/cos72= sin(90-18)/ cos72= cos72/ cos72=1

sin18/cos72sin(90-72)/cos72cos72/cos721

sin18°/cos72°= sin(90°-72°)/cos72°= cos72°/cos/72°= 1

sin72/cos72=1 is correct answer



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