1.

Prove the following : [[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]]=0

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SOLUTION :`[[1,bc,a(B+C)],[1,ca,b(c+a)],[1,AB,c(a+b)]] C_3rarrC_3+C_2`
`[[1,bc,ab+bc+ca],[1,ca,ab+bc+ca],[1,ab,ab+bc+ca]]`
=`(ab+bc+ca)[[1,bc,1],[1,ca,1],[1,ab,1]]`=0
`(therefore C_1 and C_3 are identical)`


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