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Prove the following : 8sin^4(1/2theta)-8sin^2(1/2theta)+1=cos2theta |
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Answer» SOLUTION :R.H.S. = `cos2theta=1-2SIN^2theta` =`1-2xx(2sin(theta/2)COS(theta/2))^2` `1-8sin^2(theta/2)cos^2(theta/2)` `1-8sin^2(theta/2)(1-sin^2(theta/2))` `1-8sin^2(theta/2)+8sin^4(theta/2)` = L.H.S. |
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