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Prove the following: (i) sin θ sin(90o−θ)−cos θ cos (90o−θ)=0 (ii) cos(90o−θ)sec(90o−θ)tan θcosec(90o)sin(90o−θ)cot(90o−θ)+tan (90o−θ)cot θ=2 (iii) tan (90o−A)cot Acosec2 A−cos2 A=0 (iv) cos(90o−A)sin(90o−A)tan(90o − A)=sin2 A (v) sin(50o+θ)−cos(40o−θ)+tan1o tan 10o tan 20o tan 70o tan 80o tan 89o=1 |
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Answer» Prove the following: (i) sin θ sin(90o−θ)−cos θ cos (90o−θ)=0 |
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