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Prove the following : sinA+sin3A+sin5A =sin3A(1+2cos2A)

Answer»

SOLUTION :L.H.S. = sinA+SIN3A+sin5A
= sin3A+sin5A+sinA
sin3A+2sin5A+A/2cos5A-A/2
= sin3A+2sin3Acos2A
sin3A(1+2cos2A)=R.H.S.


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