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Prove the following : sinA+sin3A+sin5A =sin3A(1+2cos2A) |
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Answer» SOLUTION :L.H.S. = sinA+SIN3A+sin5A = sin3A+sin5A+sinA sin3A+2sin5A+A/2cos5A-A/2 = sin3A+2sin3Acos2A sin3A(1+2cos2A)=R.H.S. |
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