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Prove the following : sinA-sin3A+sin5A= sin3A(2cos2A-1)

Answer»

SOLUTION :L.H.S. = sinA-SIN3A+sin5A
= sinA+sin5A-sin3A
=sin5A+sinA-sin3A
2sin5A+A/2cos5A-A/2-sin3A
2sin3Acos2A-sin3A
sin3A(2cos2A-1)=R.H.S.


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