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Prove trahectry of projectile is parabolic

Answer» Motion in horizontal direction u=ucos○ a=0 s=X from s=ut+1/2at^2 t=x/ucos○Now motion in vertical direction u=usin○ a=-g t=x/ucos○ now from same equation s=usin○.x/ucos○ +1/2 (-g) x2/u2cos2● solving this we get s=tan●x-1/2 (g/u2cos2●) x2 which is a equation of quadratic so path of projectile is parabolic


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