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Prussian blue isA. `K_(3)[Fe(CN)_(6)]`B. `K_(4) [Fe(CN)_(6)]`C. `Kfe[Fe(CN)_(6)]`D. `Fe_(4)[Fe(CN)_(6)]`

Answer» Prussian blue in `K overset(III)(Fe)[overset(II) (Fe) (CN)_(6)]`


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