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Prussion blue is formed when :A. Ferrous sulphate reacts with `FeCI_(3)`B. Forric sulphatee reacts with `K_(4)[Fe(CN)_(6)]`C. Ferrous ammonium sulphatee reacts with `FeCI_(3)`D. Ammonium sulphate reacts with `FeCI_(3)` |
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Answer» Correct Answer - b `2Fe_(2)(SO_(4))_(3) + 3K_(4)[Fe(CN)_(6)] rarr underset("Prussian blue")(Fe_(4)[Fe(CN)_(6)]_(3))+6K_(2)SO_(4)` |
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