`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=p_(2)=1atm`

`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be

1.	`Pt(Cl_(2))(p_(1))\|HCl(0.1M)\|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=p_(2)=1atm`
Answer» Correct Answer - c In case of `-ve` ion, cell is spontaneous if `[m_(1)^(c-)]_(a)gt[m_(2)^(c-)]_(c)` or `(p_(2))_(c)gt(p_(1))_(a)` and vice versa. This is only possible , when `p_(2)gtp_(1) or c_(1)gtc_(2) or M_(1)gtM_(2)`.

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`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=p_(2)=1atm`

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