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Pulling force making an angle `theta` to the horizontal is applied on a block of weight `W` placed on a horizontal table. If the angle of friction is `alpha`, then the magnitude of force is `alpha` , then the magnitude of force required to move the body is equal toA. `(W"Cos"phi)/("Cos"(theta-phi))`B. `(W"sin"phi)/("Cos"(theta-phi))`C. `(W"Tan"phi)/("Sin"(theta-phi))`D. `(W"Sin"phi)/("Tan"(theta-phi))` |
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Answer» Correct Answer - B `N +P sin theta = mg, f = mu_(k) N` . |
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