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Pure benzene freezes at `5.45^(@)C` at a certain place but a 0.374m solution of tetrachloroethane in benzene freezes at `3.55^(@)C`. The `K_(f)` for benzene isA. 5.08 K kg `"mol"^(-1)`B. 508 K kg `"mol"^(-1)`C. 0.508 K kg `"mol"^(-1)`D. `50.8^(@) C `kg `"mol"^(-1)` |
Answer» Correct Answer - A `K_(f) = Delta T_(f) // m = (5.45 - 3.55) // 0.374` `= 5.08 K kg "mol"^(-1)` |
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