Pure H_(2)O_(2)is not very stable and decomposes in the presence of light or on standing or heating overset((-1))(H_(2)O_(2l))+overset((2-)) (H_(2)O_((l)))+overset((0))(O_(2(g))) The oxidation state of oxygen in H_(2)O_(2) is 1 it is oxidistion state of zero in O_(2) and is reduced to an oxidation state of -2 in H_(2)O. Thus, this decomposition is an example of auto oxidation reduction reaction or disproportionation reaction. 30-volume, hydrogen peroxide means

Pure H_(2)O_(2)is not very stable and decomposes in the presence of li

1.	Pure H_(2)O_(2)is not very stable and decomposes in the presence of light or on standing or heating overset((-1))(H_(2)O_(2l))+overset((2-)) (H_(2)O_((l)))+overset((0))(O_(2(g))) The oxidation state of oxygen in H_(2)O_(2) is 1 it is oxidistion state of zero in O_(2) and is reduced to an oxidation state of -2 in H_(2)O. Thus, this decomposition is an example of auto oxidation reduction reaction or disproportionation reaction. 30-volume, hydrogen peroxide means
Answer» 30% of `H_2O_2` by VOLUME 30g of `H_2O_2` solution contains 1g of `H_2O` `1 cm^3`of solution liberates `30 cm^3`of DIOXYGEN gas at STP `30cm^3` of the solution contains ONE mole of `H_2O_2` Solution :30 -volume,HYDROGEN PEROXIDE means `1 cm^3` of solution liberates `30 cm^3` of dioxygen gas at STP