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Pure sulphur was burnt. the gaseous products are `SO_(2)=60%` (mol), `SO_(3)=20%` (mol) and `O_(2)=20%` (mol). If initially 50 moles of sulphur was taken then how many moles of `O_(2)` should be taken.A. 110B. 68.75C. 55D. 50 |
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Answer» Assume that mole of product mixture =x mole `n_(a)=50=xxx0.6+x xx0.2-0.8x` `x=(50)/(0.8)=(500)/(8)=62.5` `n_(o_(2))` remain=62.5xx0.2-12.5 `n_(o)=2xxn_(SO_(2))+3xxn_(SO_(3))=2xx x xx0.6+3xx x xx0.2` `n_(o)=1.2x+0.6x=1.8x=1.8xx62.5` `n_(o_(2))=(1.8xx65)/(2)=0.9xx65=56.25` `n_(o_(2))` total require `=56.25+12.5=68.75` |
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