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Q. 12. If sec 34°x, then find the value of0cot 56+cosec 56°

Answer»

sec 34°=x=>sec² 34°=x²=>1+tan² 34°=x²=>tan² 34°=x²-1=>tan²(90°-56°)=x²-1=>cot² 56°=x²-1

And sec 34°=x=>sec(90°-56°)=x=>cosec 56°=x

∴cot² 56°+cosec 56°=x²+x-1


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