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Q. 3. The sum of the 4th and 8th terms of an A.P. is 24 and the sum of the 6a and(CBSE 2008, 09, Al)10th term is 44. Find the first three terms of the A.P

Answer»

A4+a8=24a+3d+a+7d=242a+10d=24. .........1

a6+a10=34a+5d+a+9d=342a+14d=34. .,.......2Subtracting 2 from 12a+14d=342a+10d=24- - -4d=10d=4/10or 2/5Put d= 2/5 in 12a+10×2/5=242a+4=242a=24-42a=20a=10

first term=a=10second term=a+d=10+(2/5)=52/5third term=a+2d=10+4/5=54/5

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