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Q:4)Draw two carbon compounds for following functional groupsAldehydeKetoneCarboxylic acidAlkene |
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Answer» Explanation: For Aldehyde 1) CH3-CH2-CHO=Propanal. 2)CH3-CH2-CH2-CHO=Butanal. For Ketone 1)CH3-CO-CH3=Propanone. 2)CH3-CO-CH2-CH3=Butanone. For Carboxylic group 1)CH3-COOH=Ethanoic acid. 2)CH3-CH2-COOH=Propanoic acid. For ALKENE 1)CH2=CH2 :- Ethene. 2)CH2=CH-CH3 :- Propene |
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