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Q-6 A current of 1 A flow through a resistor of 10 columb for 2sec.Heat produce through it is20J40J10J15 J |
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Answer» Explanation:Heat produced , H=I 2 Rt here, t H 5 =I 5 2 R 5 =10⇒I 5 = 5 10 = 2 . This is the CURRENT through resistor 5Ω. Voltage across resistor 5Ω is V 5 =I 5 R 5 = 2 ×5=5 2 V As resistors (4,6) and 5 are in parallel, so POTENTIAL across (4,6) is equal to V 5 . As resistor 4 and 6 are in series so current through each resistor I 4 =I 6 = 4+6 V 5 = 4+6 5 2 = 2 2 Heat produce in resistor 4 per sec =I 4 2 R 4 =( 2 2 ) 2 ×(4)=2cal/sec |
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