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Q-6 A current of 1 A flow through a resistor of 10 columb for 2sec.Heat produce through it is20J40J10J15 J​

Answer»

Explanation:Heat produced , H=I  2 Rt here,   t H  5 ​  ​ =I  5 2 ​ R  5 ​ =10⇒I  5 ​ =  5 10 ​  ​ =  2 ​  . This is the CURRENT through resistor 5Ω. Voltage across  resistor 5Ω is V  5 ​ =I  5 ​ R  5 ​ =  2 ​ ×5=5  2 ​ V As resistors (4,6) and 5 are in parallel, so POTENTIAL across (4,6) is equal to V  5 ​ . As resistor 4 and 6 are in series so current through each resistor I  4 ​ =I  6 ​ =  4+6 V  5 ​  ​ =  4+6 5  2 ​  ​ =  2 2 ​  ​  Heat produce in resistor 4 per sec =I  4 2 ​ R  4 ​ =(  2 2 ​  ​ )  2 ×(4)=2cal/sec



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