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Q.8. Find the number of words with or without meaning which can be made using all the letters of the word AGAIN .If these words are written as in a dictionary, what will be the 47word? |
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Answer» Number of A's in AGAIN = 2 Number of G, I \(\&\) N in AGAIN = 1 (each). ∴ Total words formed by AGAIN \(= \frac{5!}{2! \, 1! \, 1! \,1!}\) \(= \frac{120}{2} = 60.\) Total number of words starting with \(A = 4! = 24\) Total number of words starting with \(G = \frac{4!}{2!} = \frac{24}{2} = 12\) Total number of words starting with \(I = \frac{4!}{2!} = \frac{24}{2} = 12\) Last word which starts by I is 48th word = INGAA ∴ 47th word = INAGA. |
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