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Q is energy released in the decay m_(x) is atomic mass of parent nucleus m_(y) is atomic mass of daughter nucleus and m_(e) is mass of elctron then match the following: `{:(,"Column-I",,"Column-II"),("(A)","k capture",,(P) Q=(m_(x)-m_(y))c^(2)),("(B)",beta^(-) decay,,(Q)Q=(m_(x)-m_(y)-m_(c))c^(2)),("(C)",beta^(+) decay,,(R)Q=(m_(x)-m_(y)-2m_(e))c^(2)),(,,,(S)Q=(m_(x)-m_(y)+2m_(e))c^(2)),(,,,):}` |
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Answer» Correct Answer - [(A)P(B)P(C)R] `Q= Delta mc^(2)` |
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