Q. Solve the following equaelimination method to makcoefficients.7. 2x

1.	Q. Solve the following equaelimination method to makcoefficients.7. 2x + y = 13, 5x â€“ 3y = 16
Answer» 2x+3y=13----------(i)5x-3y=22 ------------(ii)-----------------7x = 35, x=5putting the value of x in eq 12x+3y=132(5) + 3y=1310-13=3y-3=3yY=-1 2x+3y=13___________(i) 5x-3y=22___/___________(ii) __________________7x=35; x=35/7=5, 2(5)+3y=13, 3y=13-10=3; y =3/3=1; x=3; y=1 927872278272829398383

Q. Solve the following equaelimination method to makcoefficients.7. 2x + y = 13, 5x â€“ 3y = 16

Answer»

2x+3y=13----------(i)5x-3y=22 ------------(ii)-----------------7x = 35, x=5putting the value of x in eq 12x+3y=132(5) + 3y=1310-13=3y-3=3yY=-1

2x+3y=13___________(i) 5x-3y=22___/___________(ii) __________________7x=35; x=35/7=5, 2(5)+3y=13, 3y=13-10=3; y =3/3=1; x=3; y=1

927872278272829398383