Q24 Find the height of the cone formed by a sector of radius 6cm andse

1.	Q24 Find the height of the cone formed by a sector of radius 6cm andsectorial angle 120Â°
Answer» LET WE CUT OUT THE SECTOR FROM THE CIRCLE. LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 6 = 4 PIE. NOW, THE SECTOR IS ROLLED TO MAKE A CONE. RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 6 UNITS. LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 4 PIE. 2 PIE r = 4PIE. RADIUS OF THE CONE= 2 UNITS. HEIGHT OF THE CONE= h h2= 6²- 4²= 12, h= √12.

Q24 Find the height of the cone formed by a sector of radius 6cm andsectorial angle 120Â°

Answer»

LET WE CUT OUT THE SECTOR FROM THE CIRCLE.

LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 6 = 4 PIE.

NOW, THE SECTOR IS ROLLED TO MAKE A CONE.

RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 6 UNITS.

LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 4 PIE.

2 PIE r = 4PIE.

RADIUS OF THE CONE= 2 UNITS.

HEIGHT OF THE CONE= h

h2= 6²- 4²= 12, h= √12.