Q3. Match the ColumnsMatch the Columns I with Column II.Column 1 Colum

1.	Q3. Match the ColumnsMatch the Columns I with Column II.Column 1 Column 2 (a) Real image (i)Cannot be formed on the screen (b) Magnified image (ii)Upside down image.(c) Erect image (iii) Smalier than the object.(d) Diminished image (iv) Upright image (e) Virtual image (v) Bigger than the object.(f) Inverted image (vi) Formed on the screen.
Answer» Answer: positive magnification means upright image with respect to object negative magnification means inverted image with respect to object. magnification greater than 1 means image SIZE is larger than object size and magnification less than 1 means image size is less than object size. In case of convex MIRROR image is always reduced in size and upright, so 0 In case of concave mirror image is inverted-small, inverted large, upright-large, so m>1 and m<0 real image is only formed by concave mirror and possible results are inverted-small or inverted large image, So, m<0 Virtual image formed by concave mirror is upright-large, while virtual image formed by convex mirror are upright-small. So, m>0 So, correct match is A-2,3 B-2,3 C-2,4 D-1,4

Q3. Match the ColumnsMatch the Columns I with Column II.Column 1 Column 2 (a) Real image (i)Cannot be formed on the screen (b) Magnified image (ii)Upside down image.(c) Erect image (iii) Smalier than the object.(d) Diminished image (iv) Upright image (e) Virtual image (v) Bigger than the object.(f) Inverted image (vi) Formed on the screen.

Answer»

Answer:

positive magnification means upright image with respect to object

negative magnification means inverted image with respect to object.

magnification greater than 1 means image SIZE is larger than object size

and magnification less than 1 means image size is less than object size.

In case of convex MIRROR image is always reduced in size and upright, so 0

In case of concave mirror image is inverted-small, inverted large, upright-large, so m>1 and m<0

real image is only formed by concave mirror and possible results are inverted-small or inverted large image, So, m<0

Virtual image formed by concave mirror is upright-large, while virtual image formed by convex mirror are upright-small. So, m>0

So, correct match is

A-2,3

B-2,3

C-2,4

D-1,4