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Qi. Find the value of k for which 2x2 kx + k-0 has real and equal roots.02 Ifthe dictn |
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Answer» If the equation has equal roots, b² - 4ac = 0.b² - 4ac = 0a = 2b = -kc = k (-k)² - 4*2*k = 0k² - 8k = 0k(k - 8) = 0k = 0 and k - 8 = 0k = {0,8} Hence, the values of k are 0 and 8. |
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