Quantity I- In a question paper probability of a question not being answered by three students is 0,5, 0.4,0.7 respectively. Find the probability that at most two students will solve the question. Quantity II- Dipak have 5 black balls & 7 white balls, in his bag. If three balls are drawn at random from bag, then find probability of getting at least 1 black ball. Quantity III- nirmal speaks the turth 4 out of 5 times, and Puja speaks the truth 6 out of 7 times. What is the probability that they will contradict each othre in stating the same fact?

Quantity I- In a question paper probability of a question not being an

1.	Quantity I- In a question paper probability of a question not being answered by three students is 0,5, 0.4,0.7 respectively. Find the probability that at most two students will solve the question. Quantity II- Dipak have 5 black balls & 7 white balls, in his bag. If three balls are drawn at random from bag, then find probability of getting at least 1 black ball. Quantity III- nirmal speaks the turth 4 out of 5 times, and Puja speaks the truth 6 out of 7 times. What is the probability that they will contradict each othre in stating the same fact?
Answer» (@,&) (#,@) (@,@) (**,#) Solution :Quantity -I Probablity of at most two students wil SOLVE the question =1- probability of all three studrnts will solve the question `=1-(0.5)xx(0.6)xx(0.3)=1-0.09=0.91` Quantity II- Total balls `=5+7=12` Probability of getting at least 1 BLACK BALL =1- probability of no black ball. `=1-7/44=37/44=0.84` Quantity III- P (Nirmal speak truth) =`4/5` P (Puja speak truth )`=6/7` Required probability `=4/5xx1/7+1/5xx6/7=10/35=2/7~~0.28` Quantity I `GT` Quantity `II gt` Quantity III