Question 29The first member of alkyne homologous series is(a) ethyne(b – InterviewSolution

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1.	Question 29The first member of alkyne homologous series is(a) ethyne(b) ethene(c) propyne(d) methane
Answer» Question 29 The first member of alkyne homologous series is (a) ethyne (b) ethene (c) propyne (d) methane

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