InterviewSolution
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InterviewSolution
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Question 3 ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD⊥BC (see figure). To prove that ∠BAD=∠CAD, a student proceeded as follows. In ΔABD and ΔACD, we have AB= AC [given] ∠B=∠C [because AB=AC] And ∠ADB=∠ADC Therefore,ΔABD≅ΔACD [by AAS congruence rule] So,∠BAD=∠CAD [by CPCT] What is the defect in the above arguments? |
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Answer» Question 3 ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD⊥BC (see figure). To prove that ∠BAD=∠CAD, a student proceeded as follows.  In ΔABD and ΔACD, we have AB= AC [given] ∠B=∠C [because AB=AC] And ∠ADB=∠ADC Therefore,ΔABD≅ΔACD [by AAS congruence rule] So,∠BAD=∠CAD [by CPCT] What is the defect in the above arguments? |
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