Question 6 Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar(APB)×ar(CPD)=ar(APD)×ar(BPC)

Question 6 Diagonals AC and BD of a quadrilateral ABCD intersect each

1.	Question 6 Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar(APB)×ar(CPD)=ar(APD)×ar(BPC)
Answer» Question 6 Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that $a r (A P B) \times a r (C P D) = a r (A P D) \times a r (B P C)$