Question 7 The curved surface area of a frustum of a cone is π(r1+r2)l, where l=√h2+(r1+r2)2 r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.

Question 7 The curved surface area of a frustum of a cone is π(r1+r2)

1.	Question 7 The curved surface area of a frustum of a cone is π(r1+r2)l, where l=√h2+(r1+r2)2 r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.
Answer» Question 7 The curved surface area of a frustum of a cone is $π (r_{1} + r_{2}) l$ , where $l = \sqrt{h^{2} + (r_{1} + r_{2})^{2}}$ $r_{1} a n d r_{2}$ are the radii of the two ends of the frustum and h is the vertical height.

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Question 7 The curved surface area of a frustum of a cone is π(r1+r2)l, where l=√h2+(r1+r2)2 r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.

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