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Question : In the figure, masses m_(1), m_(2) and M are 20kg, 5kg, and 50kg respectively. The coefficient of friction between M and ground is zero. The coefficient of friction between m_(1) and M and that between m_(2) and ground is 0.3. The pulleys and the strings are massless. The string is perfectly horizontal between P_(1) and m_(1) also between P_(2) and m_(2). The string is perfectly vertical between P_(1) and P_(2). An external horizontal force F is applied to the mass M. Let the magnitude of the force of friction between m_(1) and M be f_(1) and that between m_(2) and ground be f_(2). For a particular F it is found that f_(1) = 2f_(2). [Take g = 10 m/s^(2)] (i) Findf_(1)in Newton (ii) Find f_(2)in Newton (iii) Find F in Newton (iv) Find tension in the string in Newton (v) Find acceleration of the masses inm//s^(2)

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ANSWER :TRUE


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