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Question : Individuals homozygous for ab genes were crossed with wild type (++). The F_(1) hybrid thus produced was test crossed. It produces progeny in following proportion. Now, calculate the distance between a and b genes.

Answer»

Solution :NUMBER of RECOMBINANTS`=115+105=220`
Number of off SPRING `=900+880+115+105`
=2000
DISTANCE between a and b genes
`=220/2000xx100=11` Map units.


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