1.

Question : Michaelis constant K_(m) is equla to

Answer»

`(K_(1))/(K_(2)-K_(3))`
`(K_(1)+K_(2))/(K_(1))`
`(K_(2)-K_(3))/(K_(1))`
`(K_(1)-K_(2))/(K_(3))`

ANSWER :B


Discussion

No Comment Found