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Question : NADP^(+) is reduced to NADPH in

Answer»

PS-I
PS-II
Calvin cycle
Non-cyclic photophosphorylation

Solution :In photosynthesis during non-cyclic photophoshorylation involving both PS-I and PS-II, electrons released during photolysis of water are transferred to PS-II and then PS-I VIA a series of electron carriers. `P_(700)` of PS-I releases electron after ABSORBING light energy This electron passes through CHLOROPHYLL X, Fe-S, ferredoxin and finally to `NADP^(+).NADP^(+)` combines with `H^(+)` (released during photolysis) with the help of NADP REDUCTASE to form NADPH.
`NADP^(+)+2e^(-)+H^(+)overset("NADP reductase")toNADPH`


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