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Answer» An action potential in NEURON A causes a depolarisation in neuron B. An action potential in neuron B causes a depolarisation in neuron C. Simultaneous action potentials in A and B will cause hyperpolarisation of neuron C. Simultaneous action potentials in A and B will cause less depolarisation of neuron C than if only neuron A fired an action potential. Solution :Once neurotransmitters are released from the pre-synaptic axon terminal, they diffuse across the cleft.This results in binding of neurotransmitter to receptor and OPENING or closing of specific ion channels in the post-synaptic plasma membrane.Usually at an EXCITATORY snapse, channels in the post-synaptic cell that are permeable to `Na^+, K^+` and other small positive ions open, but `Na^+` flux dominates, because it has the largest electrochemical gradient.At inhibitory synapses, channels to `Cl^-` or `K^+` open.In the given SITUATION, the neuron B sends inhibitory pre-synaptic signals onto post-synaptic neuron C which would summate (subtract from ) with the AMPLITUDE of excitatory pre-synaptic signal caused by neuron A.Therefore depolarisation will be of lower amplitude.
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