Question : Water potential of a flaccid cell will be

1.	Question : Water potential of a flaccid cell will be
Answer» `Psi_(w)=Psi_(s)` `Psi_(s)=Psi_(rho)` `Psi_(w)=0` Ψ w=Ψ s-Ψ p Solution :If plant cell happens to be bathed in hypertonic solution, it loses water through the process of EXOSMOSIS. The loss of wate is first from CYTOPLASM and then central vacuole. As a result, the protoplast is reduced in size. This decreases turgor pressure or pressure potential `(psi_(p))` and corresponding wall pressure. solute potentail becomes slightly more NEGATIVE DUE to loss of water. The cell ATTAINS a minimum size when turgor pressure is zero/pressure potential `(psi_(p))` is zero. Therefore, `psi_(w) = psi_(s) + psi_(p)` or `psi_(w) = psi_(s) (as psi_(p) = 0)` A cell which is deficient in turgor is called flaccid.

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