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Rachana borrowed a certain sur at the rate of 15% per annum. If she paid at the end of twowears 1290 an interest compounded annually, find the sum she borrowed. |
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Answer» let principal pA=p(1+15/100)^2=p(115/100)^2= p(23/20)^2=p(529/400)Interest= A -p1290=p(529/400)-p =p(529-400/400)1290*400/129=p4000=p let the money she borrowed be X. then we have:X -p(1+15/100)^2 then solve it and the answer is 4000 4000the answer is correct 4000 is correct answer. |
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