Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…A. 9cm and 18cmB. 6cm and 12cmC. 3cm and 6cmD. 4.5cm and 9cm

Radii of curvature of a canverging lends are in the ration 1:2. Its fo

1.	Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…A. 9cm and 18cmB. 6cm and 12cmC. 3cm and 6cmD. 4.5cm and 9cm
Answer» Correct Answer - D Given `(R_(1))/(R_(2))=(1)/(2),f=6`cm and `mu=1.5` Let, `R_(1)=R and R_(2)=2R` We know that the focal length of converging lens by using releationg , `(1)/(f)=(mu-1)[(1)/(R_(1))-(1)/(R_(2))]` Substituting all the values, we get `R=4.5cm` `R_(1)=4.5cm` and `R_(2)=2xx4.5=9cm`

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Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…A. 9cm and 18cmB. 6cm and 12cmC. 3cm and 6cmD. 4.5cm and 9cm

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