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Radio Ceylon broadcasts at `25 m`. What is the frequency of the station ? |
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Answer» Correct Answer - `1.2 xx 10^7 Hz` Here, `lamda = 25 ,` speed of radio waves, `v = 3 xx 10^8 m//s` (speed of light in vacuum) Thus, `v = (v)/(lamda) = (3 xx 10^8)/(25) = 1.2 xx 10^7 Hz`. |
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