Radioactive material decays by simultaneous emission of two particles with respective half-lives 1620 and 810 years. The time, in years, after which one-fourth of the material remains?(a) 1080(b) 2430(c) 3240(d) 4860This question was posed to me in an interview.This interesting question is from Nucleus topic in division Nucleus of Physics – Class 12

Radioactive material decays by simultaneous emission of two particles

1.	Radioactive material decays by simultaneous emission of two particles with respective half-lives 1620 and 810 years. The time, in years, after which one-fourth of the material remains?(a) 1080(b) 2430(c) 3240(d) 4860This question was posed to me in an interview.This interesting question is from Nucleus topic in division Nucleus of Physics – Class 12
Answer» The CORRECT option is (a) 1080 The explanation: N = N0e^-(λ1 + λ2) t. 4 = e^(λ1 + λ2) t. t = \(\frac {(2 \TIMES 1620 \times 810)}{(2430)}\) = 1080 year.

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