Radius of a star acting like perfect black body is R, then at what temperature the rate of radiation will be Q ? (Where sigma= Stefun - Boltzman constant)

Radius of a star acting like perfect black body is R, then at what tem

1.	Radius of a star acting like perfect black body is R, then at what temperature the rate of radiation will be Q ? (Where sigma= Stefun - Boltzman constant)
Answer» `(Q)/(4piR^(2)SIGMA)` `((Q)/(4piR^(2)sigma))^(-1/2)` `((4piR^(2)Q)/(sigma))^(1/4)` `((Q)/(4piR^(2)sigma))^(1/4)` SOLUTION :From Stefan-Boltzmann.s LAW, Here, Q is taken in place of P. `:.Q=AsigmaeT^(4)` `:.Q=4pir^(2)sigmaT^(4)""(because e=1)` `:.T=((Q)/(4pir^(2)sigma))^(1/4)`