Radius of an air bubble at certain depth of Indian ocean is r and it b

1.	Radius of an air bubble at certain depth of Indian ocean is r and it becomes 18r, when air bubble rises to the top surface of the ocean. If t cm of water be the atmospheric pressure, then the depth of the ocean is(a) 3835 t cm(b) 3400 t cm(c) 4852 t cm(d) 5831t cm
Answer» Answer is : (d) 5831t cm Let the depth of Indian ocean is x cm \(\therefore p_1V_1=p_2V_2(tdg+xdg)\)\(\left(\frac{4}{3}\pi r^3\right)\) \(=tdg\left[\frac{4}{3}\pi (18r)^3\right]\) (t + x) = t x 18³ 18³t - t = x So, x = t 5831 cm = 5831 t cm

Radius of an air bubble at certain depth of Indian ocean is r and it becomes 18r, when air bubble rises to the top surface of the ocean. If t cm of water be the atmospheric pressure, then the depth of the ocean is(a) 3835 t cm(b) 3400 t cm(c) 4852 t cm(d) 5831t cm

Answer»

Answer is : (d) 5831t cm

Let the depth of Indian ocean is x cm

\(\therefore p_1V_1=p_2V_2(tdg+xdg)\)\(\left(\frac{4}{3}\pi r^3\right)\) \(=tdg\left[\frac{4}{3}\pi (18r)^3\right]\)

(t + x) = t x 18³

18³t - t = x

So, x = t 5831 cm = 5831 t cm

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Radius of an air bubble at certain depth of Indian ocean is r and it becomes 18r, when air bubble rises to the top surface of the ocean. If t cm of water be the atmospheric pressure, then the depth of the ocean is(a) 3835 t cm(b) 3400 t cm(c) 4852 t cm(d) 5831t cm

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