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Radius of curvature \( 20 cm \) and \( 100 cm \). What is the power of lens in diopter? |
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Answer» Given, R1 = 20 cm R2 = 100 cm Then focal length \(f_1 = \frac {R_1}2\) \(f_1 = \frac {20}2\) f1 = 10 cm So power of 20cm curvature radius lens \(p_1= \frac{100} {f_1}\) \(p_1= \frac{100} {10}\) p1 = 10 D For R2 = 100 cm The focal length \(f_2 = \frac {R_2}2\) \(f_2 = \frac {100}2\) f2 = 50 cm Then power will be \( p_2=\frac{100}{f_2}\) \( p_2=\frac{100}{50}\) p2 = 2 D |
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