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Radius of gyration of a disc of mass 5 kg about a transverse axis passing through its centre is 14.14 cm. Find its radius of gyration about its diameter and hence calculate its moment of inertia about its diameter |
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Answer» SOLUTION :Radius of gyration of a disc about a transverse axis PASSING through its centre `K = sqrt((I)/(M))=sqrt((MR^(2))/(2M))=(R )/(sqrt(2))=14.14 cm` `(therefore I =(MR^(2))/(2))` Radius of the disc, `R = 14.14xxsqrt(2)=20 cm` Radius of gyration of the disc about its diameter. `K= sqrt((I)/(M))=sqrt((MR^(2))/(4M))=(R )/(2)=(20)/(2)=10 cm` Moment of inertia about its diameter = `(MR^(2))/(4)=(5(0.2)^(2))/(4)=5.00xx10^(-2)KG m^(2)` |
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