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Radius of gyration of a disc of mass 5 kg about a transverse axis passing through its centre is 14.14cm. Find its radius of gyration about its diameter and hence calculate its moment of inertia about its diameter |
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Answer» Solution :Radius of gyration of a DISC about a TRANSVERSE axis PASSING through its centre `K=sqrt((I)/(M))=sqrt((MR^(2))/(2M))=(R)/(sqrt2)=14.14cm` `(,.I=(MR^(2))/(2))` Radius of the dise, `R=14.14xxsqrt2=20cm` Radius of gyration of the disc about its diameter. `K=sqrt((I)/(M))=sqrt((MR^(2))/(4M))=(R)/(2)=(20)/(2)=10cm` Moment of inertia about its diameter = `(MR^(2))/(4)=(5(0.2)^(2))/(4)=5.00xx10^(-2)kgm^(2)` |
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