1.

Rain is falling vertically with a speed of 35ms^(-1). Winds starts blowing after sometime with a speed of 12ms^(-1) in east to west direction. In which direction should a boy waiting at a bus stop hold his umbrella?

Answer»

Solution :The velocity of the rain and the wind are represented by the vectors `v_(r) and v_(w)` in the figure and are in the direction specified by the problem. Using the rule of vector addition. We see that the RESULTANT of `v_(r) and v_(w)` is R as shown in the figure. The magnitude of R is.

`R=sqrt(v_(r)^(2)+v_(w)^(2)) = sqrt(35^(2)+12^(2))MS^(-1) = 37ms^(-1)`
The direction `theta` that R makes the vertically is GIVEN by
`tantheta=(v_(w))/(v_(r)) =(12)/(35) = 0.343 or, theta = tan^(-1)(0.343)=19^(@)`
Therefore, the boy should hold his umbrella in the vertical plane at an angle of about `19^(@)` with the vertically towards the east.


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