Saved Bookmarks
| 1. |
Raju increased the speed of moving mass ‘50 kg’ from 2 m/s to 4m/s.1. How much force will be required, if velocity change takes place with in 0.2 sec?2. How much work is done by Raju? |
|
Answer» 1. F = mass × acceleration = 50 × (4−2)/0.2 = 500N. 2. w = \(\frac{1}{2}\)mv2 – 12mu2. =\(\frac{1}{2}50\) (42 – 22) = 300 J. |
|