1.

Raju increased the speed of moving mass ‘50 kg’ from 2 m/s to 4m/s.1. How much force will be required, if velocity change takes place with in 0.2 sec?2. How much work is done by Raju?

Answer»

1. F = mass × acceleration

= 50 × (4−2)/0.2

= 500N.

2. w = \(\frac{1}{2}\)mv2 – 12mu2.

=\(\frac{1}{2}50\) (42 – 22)

= 300 J.



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