Ram joined Kota test series, where he was asked to calculates DeltaS_(sys) for a process as described below. A diathermic container (containing an ideal gas) fitted with a piston at equilibrium (without any topper) and has initial volume 600 liter. Now the external pressure is suddenly reduced to 1 bar and allowed the piston to move upward isothermally. In this process, system absorb 600 kJ heat. He calculated DeltaS _(sys) =2kJ//K but was awarded zero marks. To identify his mistake he contacted his Kota feiend Shyam and explained his problem.When shyam asked how Ram calculated DeltaS_(sys,) Ram said simple !by q//T. If you are Shyam, then help Ram in getting crrect answer (in kJ//K). [In 11=2.4]

Ram joined Kota test series, where he was asked to calculates DeltaS_(

1.	Ram joined Kota test series, where he was asked to calculates DeltaS_(sys) for a process as described below. A diathermic container (containing an ideal gas) fitted with a piston at equilibrium (without any topper) and has initial volume 600 liter. Now the external pressure is suddenly reduced to 1 bar and allowed the piston to move upward isothermally. In this process, system absorb 600 kJ heat. He calculated DeltaS _(sys) =2kJ//K but was awarded zero marks. To identify his mistake he contacted his Kota feiend Shyam and explained his problem.When shyam asked how Ram calculated DeltaS_(sys,) Ram said simple !by q//T. If you are Shyam, then help Ram in getting crrect answer (in kJ//K). [In 11=2.4]
Answer» ANSWER :5