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Range of the function `f(x)=(1+x^2)/(x^2)` is equal toA. (0,1)B. [0,1]C. `(1,oo)`D. `[1,oo)` |
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Answer» Correct Answer - C We observe that f(x) is defined for all ` x in R -{-0}` . So, domain (f)=R-{0} Let ` y=(1+x^(2))/(x^(2))`. Then, `y=(1+x^(2))/(x^(2))implies pm sqrt((1)/(y-1))` for x to be real, we must have `y-1 gt 0 implies ygt 1implies y in (1,oo)` Hence, range `(f)=(1,oo)` |
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