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Rate law for the reation `A + B to ` product is rate = `k [A]^(2) [B]` . What is the rate constant , if rate of reaction at a given temperature is `0.22 Ms^(-1)` , when [A] = 1M and [B] = 0.25 M ?A. `3.52 M^(-2) s^(-1)`B. `0.88 M^(-2) s^(-1)`C. `1.136 M^(-2) s^(-1)`D. `0.05 M^(-2) s^(-1)` |
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Answer» Correct Answer - B For reaction , ` A + B to `product `(dx)/(dt) = k[A]^(2) [ B] implies 0.22 = k(1)^(2) (0.25)` `therefore k = (0.22)/(0.25) = 0.88 M^(-2) s^(-1)` |
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