1.

Ratio of kinetic energy to potential energy of an oscillator when it is at distance `1//N` times of amplitude from mean positions inA. `n^(2)`B. `n^(2)+1`C. `1//n^(2)`D. `n^(2)-1`

Answer» Correct Answer - D
`(K.E.)/(P.E.)=((1)/(2)momega^(2)(A^(2)-x^(2)))/((1)/(2)momega^(2)x^(2))`
`=(A^(2)-x^(2))/(x^(2))=(A^(2)-(A^(2))/(n^(2)))/((1)/(n^(2))A^(2))=n^(2)-1`


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